Mathématiques

Question

Factoriser les expressions suivantes:

A= (2x - 4)(x + 3) - (x - 2)^2
B= 9 (x - 1)^2 - (x + 4)^2
C= (x - 3)(5x + 1) + (x - 3)(1 - x) + (x - 3)(2x - 7)
D= 9x^2 - 1 + (x + 2)(3x - 1) + (9x^2 - 6x + 1)

Avec justification svp je n"ai rien compris de la factorisation!

1 Réponse

  • A= (2x - 4)(x + 3) - (x - 2)^2
    a = 2(x-2)(x+3) -(x-2)²
    a = (x-2)(2x+6-x+2)
    a =(x-2)(x+8)

    B= 9 (x - 1)^2 - (x + 4)^2
    b = 3²(x-1)² -(x+4)²
    b =(3x-3-x-4)(3x-3+x+4)
    b =(2x-7)(4x+1)

    C= (x - 3)(5x + 1) + (x - 3)(1 - x) + (x - 3)(2x - 7)
    c =(x-3)(5x+1+1-x+2x-7)
    c =(x-3)(6x-5)

    D= 9x^2 - 1 + (x + 2)(3x - 1) + (9x^2 - 6x + 1)
    d =(3x-1)(3x+1) +(x+2)(3x-1) +(3x-1)²
    d =(3x-1)(3x+1+x+2+3x-1)
    d =(3x-1)(7x+2)

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