Mathématiques

Question

Factoriser l'expression
Factoriser l'expression A = (6-5x)(4x+3)-(4x+3)(7-2x)
Dévlopper l'expression A.

2 Réponse

  • bonjour,

    (4x+3)(6-5x-7+2x)
    (4x+3)(-3x-1)


    a = 24x+18-20x²-15x -(28x-8x²+21-6x)
    a = -20x²+9x+18 +8x²-22x-21
    a = -12x² -13x-3
  • 1) A = (6 - 5x) (4x + 3) - (4x + 3) (7 - 2x)
    A = (4x + 3) [(6 - 5x) - (7 - 2x)]
    A = (4x + 3) (6 - 5x - 7 + 2x)
    A = (4x + 3) (- 3x - 1)

    2) A = (6 - 5x) (4x + 3) - (4x + 3) (7 - 2x)
    A = 6 X 4x + 6 X 3 - 5x X 4x - 5x X 3 - [4x X 7 + 4x X (- 2x) + 3 X 7 + 3 X (- 2x)]
    A = 24x + 18 - 20x² - 15x - (28x - 8x² + 21 - 6x)
    A = 24x + 18 - 20x² - 15x - 28x + 8x² - 21 + 6x
    A = - 12x² - 13x - 3

Autres questions