resoudre l'equation x²-10x+20,16=0

bonjour,

x²-10x+20,16 = (x-5)²-4,84

(x-5-2,2)(x-5+2,2) = 0

(x-7,2)(x-2,8) = 0

x = 7,2
x = 2,8

x² - 10x + 16 = 0
(x - 5)² - 9 = (x - 5)² - 3²
(x - 5 + 3) (x - 5 - 3) = 0
(x - 2) (x - 8) = 0
x - 2 = 0               ou                 x - 8 = 0
x = 2                    ou                 x = 8

Deux solutions : S {2 ; 8]