g(x)= (2x-1) exposant3 -(2x-1)xx-8)au carré =0

Bonjour Yariek

[tex](2x-1)^3-(2x-1)(x-8)^2=0\\\\(2x-1)(2x-1)^2-(2x-1)(x-8)^2=0\\\\(2x-1)[(2x-1)^2-(x-8)^2]=0\\\\(2x-1)[(2x-1)+(x-8)][(2x-1)-(x-8)]=0\\\\(2x-1)(2x-1+x-8)(2x-1-x+8)=0\\\\(2x-1)(3x-9)(x+7)=0\\\\2x-1=0\ \ ou\ \ 3x-9=0\ \ ou\ \ x+7=0[/tex]

[tex]\\\\2x=1\ \ ou\ \ 3x=9\ \ ou\ \ x=-7\\\\x=\dfrac{1}{2}\ \ ou\ \ x=\dfrac{9}{3}\ \ ou\ \ x=-7\\\\\boxed{x=\dfrac{1}{2}\ \ ou\ \ x=3\ \ ou\ \ x=-7}\\\\\boxed{x=0,5\ \ ou\ \ x=3\ \ ou\ \ x=-7}[/tex]