Salut tout le monde, Je ne comprends pas question. Sésamaths 3emaths Résous les équations produit suivantes. a. (x − 4)(x + 9) = 0 b. (4x − 1)(9x − 2) = 0 c. (3

a. (x − 4)(x + 9) = 0

x-4 =0                            x+9 = 0
x = 4                                x = -9

b. (4x − 1)(9x − 2) = 0

4x-1 =0                     9x-2 =0
4x = 1                          9x = 2
x = 1/4                          x = 2/9


c. (3x + 2)2 = 0

3x+2 =0
3x = -2
x = -2/3

a. x - 4 = 0   ...   x+9 = 0 
a. x=4  ...   x= -9 

b. 4x -1 = 0   ...   9x - 2 = 0
4x = 1   ... 9x = 2 
x = 1/4   ... x = 2/9
x = 0.25
c. 6x + 4 = 0
6x = - 4 
x = -4/6