Mathématiques

Question

Aider moi svp please please Please
Aider moi svp please please  Please
Aider moi svp please please  Please

1 Réponse

  • Bonjour,
    1-
    f(1/3) = (1/3 - 1)/(1/3 + 3) =(-2/3)/(4/3) = (-2/3) x 3/4 = -1/2
    2-
    A, B et C n’appartiennent pas à la courbe et d lui appartient
    3-
    h≠0
    f(-3+h) = (-3+h-1)/(-3+h+3) = (h-4)/h
    f(-3-h) = (-3-h-1)/(-3-h+3) = (-h-4)/-h = -(h+4/-h = (h+4)/h
    f(-3+h) + f(-3-h) = (h-4)/h + (h+4)/h = 2h/h = 2