Bonjour quelqu'un pourrait completer le tableau ??

[tex]f(x)=(x-3)^{2} -1[/tex]
Donc,

Si x=-0.6 :
[tex]f(-0.6) \\ =(-0.6-3)^{2} -1 \\ =(-3.6)^{2} -1 \\ =12.96-1 \\ =11.96[/tex]

Si x=-0.4
[tex]f(-0.4) \\ =(-0.4-3)^{2} -1 \\ =(-3.4)^{2} -1 \\ =11.56-1 \\ =10.56[/tex]

Si x=-0.2
[tex]f(-0.2) \\ =(-0.2-3)^{2} -1 \\ (-3.2)^{2} -1 \\ =10.24-1 \\ =9.24[/tex]

Si x=0
[tex]f(0) \\ =(0-3)^{2} -1 \\ =(-3)^{2}-1 \\ = 9-1 \\ =8[/tex]

Si x=0.2
[tex]f(0.2) \\ =(0.2-3)^{2} -1 \\ =(-2.8)^{2} -1 \\ =7.84-1 \\ =6.84[/tex]

Si x=0.4
[tex]f(0.4) \\ =(0.4-3)^{2} -1 \\ =(-2.6)^{2} -1 \\ =6.76-1 \\ =5.76[/tex]

Si x=0.6
[tex]f(0.6) \\ =(0.6-3)^{2} -1 \\ =(-2.4)^{2} -1 \\ =5.76-1 \\ =4.76[/tex]